Question

Change these numbers into special numbers
$\left(i\right)28\left(ii\right)132$

Answer 1

Solution:-

(i) $28$

Given no. $=28$

Turning the no. from back to front, i.e., $82$

Adding both of them, i.e.,

$82+28=110$

Since $110$ is not a special no.

Again turning from back to end, i.e. $011$

Now again adding both, i.e.,

$110+011=121$

We got $121$ which is the required special no.

(ii) $132$

Given no. $=132$

Turning the no. from back to front, i.e., $231$

Adding both of them, i.e.,

$132+231=363$

We got $363$ which is the required special no.