Question

Characteristic impedance of a transmission line is 50$\Omega$. Input impendance of the open-circuited line is $Z_{OC}=100+j150\Omega$. When the transmission line is short-circuited, then value of the input impedance will be

• A. 7.69 + j11.54 $\Omega$
• B. 7.69 - j11.54 $\Omega$
• C. 50 $\Omega$
• D. 100 + j150 $\Omega$

Answer 1

The correct option is B 7.69 - j11.54 $\Omega$

Ans : (d)

$Z_0^2=Z_{oc}\cdot Z_{sc}$

$Z_{sc}=\frac{50\times 50}{100+j150}=\frac{50}{2+3j}=\frac{50(2-3j)}{13}$

$Z_{sc}=7.69-11.54j$