Charge 6,12and24 nano coulombs are placed on the corners of a square of side 10√2cm. The charge that must be placed at the fourth corner so that the potential at the centre of the square may be zero is
A
42nC
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B
36nC
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C
−42nC
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D
30nC
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Solution
The correct option is C−42nC
Potential due to charge particle=kq/r
Now, potential at centre =k(6nc)10+k(12)10+k(24)10+k(υ)10
given V=0 (potential at centre ) ⇒0=k(6nc)10+k(12)10+k(24)10+k(υ)10