Charge 6- 12 and 24 nano coulombs are placed on the corners of a square of side 10-2 cm- The charge that must be placed at the fourth corner so that the potential at the centre of the square may be zero is

The correct option is C 42 nC Potential due to charge #160; particle=kq/rNow, potential at centre =k(6nc)10+k(12)10+k(24)10+k(υ )10 given V = ...

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Byju's Answer

Standard XII

Physics

Potential Energy - External Viewpoint

Charge 6, 1...

Question

Charge $6, 12 a n d 24$ nano coulombs are placed on the corners of a square of side $10 \sqrt{2}$ cm. The charge that must be placed at the fourth corner so that the potential at the centre of the square may be zero is

42 n C

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36 n C

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- 42 n C

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30 n C

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Solution

The correct option is C $- 42 n C$
Potential due to charge particle=kq/r
Now, potential at centre $= \frac{k (6 n c)}{10} + \frac{k (12)}{10} + \frac{k (24)}{10} + \frac{k (υ)}{10}$

given $V = 0$ (potential at centre )
$\Rightarrow 0 = \frac{k (6 n c)}{10} + \frac{k (12)}{10} + \frac{k (24)}{10} + \frac{k (υ)}{10}$

$\Rightarrow υ = - 42 n C$

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