wiz-icon
MyQuestionIcon
MyQuestionIcon
15
You visited us 15 times! Enjoying our articles? Unlock Full Access!
Question

Charge between parallel plates :

Surface charge density is defined as the charge per unit surface area of surface charge distribution. i.e., σ=qS

Two large thin metal plates are parallel and close to each other, on their inner faces, the plates have surface charge densities of opposite sign having magnitude of 1.70×1022 Cm2 as shown in figure.
[Use ε0=8.85×1012 Fm1]

(i) The electric field E in the region in between the plates A and B is



A
12×1012 NC1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2×1010 NC1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.2×1010 NC1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.2×1012 NC1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 0.2×1010 NC1



Given, surface charge densities of plate <!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> A and B is,

σA=+1.70×1022 Cm2 ; σB=1.70×1022 Cm2

Using gauss's law, electric field in the region between the plate A and B is,

E=EA+EB=σ2ε0+σ2ε0=σε0

E=σε0=1.70×10228.85×1012

E0.2×1010 NC1

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (C) is the correct answer.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Corona Discharge
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon