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Question

Charge is uniformly distributed in a space. The net flux passing through the surface of an imaginary cube of side''a'' in the space is ϕ and in the space it is 0. The net flux passing through the surface of an imaginary sphere of radius ''a'' in the space will be:

A
ϕ
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B
34πϕ
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C
2π3ϕ
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D
4π3ϕ
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Solution

The correct option is B 2π3ϕ

External flux of a surface is given by : E.ds.

Since, the flux through the cube would be E×6a2=ϕE=ϕ6a2

therefore for a sphere, the flux would be E.×4πa2

which is equal to ϕsphere=2π3ϕ


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