Question

Charge on a originally uncharged conductor is separated by holding a positively charged rod very closely nearby, as shown in Fig. Assume that the induced negative charge on the conductor is equal to the positive charge q on the rod. Then the flux through surface $S_1$ is :

• A. $zero$
• B. $q/{\epsilon }_0$
• C. $-q/{\epsilon }_0$
• D. none of the these

Answer 1

The correct option is B $q/{\epsilon }_0$

Net charge on the conductor will be zero. So, net charge inside $S_1$ will be the charge on the rod. Hence flux through $S_1$ is $q/{\epsilon }_0$