Charged particle (charge $= q$ ; mass $= m$ ) is rotating in a circle of radius $R$ with uniform speed $V$ , Ratio of its magnetic moment ( $μ$ ) to the angular momentum ( $L$ ) is

\frac{q}{2 m}

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\frac{q}{m}

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\frac{q}{4 m}

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\frac{2 q}{m}

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Solution

The correct option is A $\frac{q}{2 m}$
Magnetic moment $μ = I A = (q ν) A$
$μ = \frac{q V}{2 π R} \times π R^{2} = \frac{q V R}{2}$
Angular momentum $L = m V R$
Ratio $\frac{μ}{L} = \frac{\frac{q V R}{2}}{m V R} = \frac{q}{2 m}$

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Charged particle (charge=q; mass=m) is rotating in a circle of radius R with uniform speed V, Ratio of its magnetic moment (μ) to the angular momentum (L) is

The correct option is A q2mMagnetic moment μ=IA=(qν)A μ=qV2πR×πR2=qVR2Angular momentum L=mVRRatio μL=qVR2mVR=q2m

Charged particle (charge $= q$ ; mass $= m$ ) is rotating in a circle of radius $R$ with uniform speed $V$ , Ratio of its magnetic moment ( $μ$ ) to the angular momentum ( $L$ ) is

The correct option is A $\frac{q}{2 m}$
Magnetic moment $μ = I A = (q ν) A$
$μ = \frac{q V}{2 π R} \times π R^{2} = \frac{q V R}{2}$
Angular momentum $L = m V R$
Ratio $\frac{μ}{L} = \frac{\frac{q V R}{2}}{m V R} = \frac{q}{2 m}$