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Capacitance of Parallel Plate Capacitor

Charges 2q ...

Question

Charges $2 q$ and $- 3 q$ are given to two identical metal plates with area of cross-section $A$ . The distance between the plates is $d$ . Find the capacitance of the plates :

A

C = \frac{ϵ_{0} A}{2 d}

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B

C = \frac{4 ϵ_{0} A}{d}

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C

C = \frac{ϵ_{0} A}{d}

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D

C = \frac{ϵ_{0} A}{4 d}

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Solution

The correct option is C $C = \frac{ϵ_{0} A}{d}$

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