Charges are placed q, q, -q and -q at the vertices of square ABCD respectively and have side l. Find intensity at the centre of the squares.

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Solution

$|_{1} | = |_{2} | = |_{3} | = |_{4} | = \frac{k q}{{(\frac{l}{\sqrt{2}})}^{2}} = \frac{2 k q}{l^{2}}$
Now, find the vertical sum
$E_{n e t} = 4 E c o s 45^{\circ}$
$= 4. \frac{2 k q}{l^{2}} - \frac{l}{\sqrt{2}} = 4 \sqrt{2} \frac{k q}{l^{2}} (a l o n g n e g a t i v e y - a x i s)$

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Charges are placed q, q, -q and -q at the vertices of square ABCD respectively and have side l. Find intensity at the centre of the squares.

|→E1|=|→E2|=|→E3|=|→E4|=kq(l√2)2=2kql2 Now, find the vertical sum Enet=4Ecos45∘ =4.2kql2−l√2=4√2kql2(along negative y−axis)

$|_{1} | = |_{2} | = |_{3} | = |_{4} | = \frac{k q}{{(\frac{l}{\sqrt{2}})}^{2}} = \frac{2 k q}{l^{2}}$
Now, find the vertical sum
$E_{n e t} = 4 E c o s 45^{\circ}$
$= 4. \frac{2 k q}{l^{2}} - \frac{l}{\sqrt{2}} = 4 \sqrt{2} \frac{k q}{l^{2}} (a l o n g n e g a t i v e y - a x i s)$