Charges of 40μC,−40μC and10μC are placed in air at the corners A, B and C respectively of an equilateral triangle of side 2cm. The resultant force on the charge at C is :
A
9000N
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B
900N
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C
4500N
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D
450N
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Solution
The correct option is A
9000N
Let 40μC charge be q and −10μC be q′. Force between q and q′F=Kqq′/r2 Force between −q and q′F=−Kqq′/r2 Force along y−axis get cancelled and force along x−axis is given by Fx=2×Kqq′/r2cos600=9000N