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How to Visualize Electric Fields

Charges Q1 ...

Question

Charges $Q_{1}$ and $Q_{2}$ are placed inside and outside respectively of an uncharged conducting shell. Their seperation is r.

The force on

Q_{1}

is zero.

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The force on

Q_{1}

k \frac{Q_{1} Q_{2}}{r^{2}}

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The force on

Q_{2}

k \frac{Q_{1} Q_{2}}{r^{2}}

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The force on

Q_{2}

is zero.

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Solution

The correct options are
A The force on $Q_{1}$ is zero.
C The force on $Q_{2}$ is $k \frac{Q_{1} Q_{2}}{r^{2}}$
As the electric field inside the conducting shell is zero , so the force on the inner charge, $Q_{1}$ will be zero.
The electric field at outside charge $Q_{2}$ due to $Q_{1}$ is $E = k \frac{Q_{1}}{r^{2}}$
Force on $Q_{2}$ is $F = Q_{2} E = k \frac{Q_{1} Q_{2}}{r^{2}}$

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Charges Q1 and Q2 are placed inside and outside respectively of an uncharged conducting shell. Their seperation is r.

The correct options are A The force on Q1 is zero. C The force on Q2 is kQ1Q2r2As the electric field inside the conducting shell is zero , so the force on the inner charge, Q1 will be zero.The electric field at outside charge Q2 due to Q1 is E=kQ1r2Force on Q2 is F=Q2E=kQ1Q2r2

Charges $Q_{1}$ and $Q_{2}$ are placed inside and outside respectively of an uncharged conducting shell. Their seperation is r.