Question

Charges $-Q$and $2Q$are placed as shown in the figure. The electric field intensity is zero at a point which is lying somewhere to the …….. .

Answer 1

1. The direction of electric fields due to$-Q$ and$2Q$ are opposite due to that they are negative and positive charges.
2. The separation due to $-Q$ is lesser than the separation of $2Q$ to equalize the electric fields.
3. So, the electric field intensity will be zero at a point when it lies left to the charge$-Q$
4. Charges $-Q$ and $2Q$are placed as shown in the figure. The electric field intensity is zero at a point that is lying somewhere to the left of the charge$-Q$