Chase can do a job in $3 h r s$ whereas Campbell can do the same job in $4 h r s$ . If they work together, how long would it take them to finish the job?

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Solution

Solve for the required time:
Given that Chase can do a job in $3 h r s$ whereas Campbell can do the same job in $4 h r s$ .
Let the total work be L.C.M. $(3, 4) = 12 u n i t s$
Work done by Chase in an hour $= \frac{12}{3} = 4 u n i t s$
Work done by Campbell in an hour $= \frac{12}{4} = 3 u n i t s$
$∴$ Total work done by Chase and Campbell together in an hour $= 3 + 4 = 7 u n i t s$
Time taken by them to finish the job together $= \frac{12}{7} = 1 \frac{5}{7} h r s$
Hence, it would take $1 \frac{5}{7} h r s$ to finish the job if they work together.

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Chase can do a job in 3hrs whereas Campbell can do the same job in 4hrs. If they work together, how long would it take them to finish the job?

Chase can do a job in $3 h r s$ whereas Campbell can do the same job in $4 h r s$ . If they work together, how long would it take them to finish the job?