CHCl3 and HF lead to the formation of a compound of fluorine of molecular weight 70. The compound is
A
Fluoroform
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B
Fluorine monoxide
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C
Fluorine dioxide
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D
Fluoromethanol
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Solution
The correct option is A Fluoroform We nknow that CHCl3+HF→CHF3+3HCl. Thus in this reaction the compound obtained in fluoroform (CHF3). As we know molecular weight of CHF3=70.