Question

Check if $(2,0)$ is the solution of the equation $x-2y=4$or not.

Answer 1

Checking if $x=2andy=0$ is the solution of $x-2y=4$or not.

We know that if the given value of the variable $x=2andy=0$ satisfies the given equation $x-2y=4$then that value will be the solution of the equation.

Put the value of $x=2andy=0$in the given equation $x-2y=4$, we get;

$L.H.S\Rightarrow 2-2\times 0=2$

But, $R.H.S\Rightarrow 4$

We can see that $L.H.S\ne R.H.S$

Hence, $x=2andy=0$ is not the solution of $x-2y=4$.