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Question
Check if given series is AP or not? If they form an AP, find the common difference d and write three more terms.
−12,−12,−12,−12,.....
−12,−12,−12,−12,.....
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Solution
The given series is −12,−12,−12,−12,⋯.
a2−a1=−12−(−12)
=0
a3−a2=−12−(−12)
=0
a4−a3=−12−(−12)
=0
This shows that the difference is same, so the given series is in A.P. with common difference 0. The next three terms are,
a5=−12+(0)
=−12
a6=−12+(0)
=−12
a7=−12+(0)
=−12
The given series is −12,−12,−12,−12,⋯.
a2−a1=−12−(−12)
=0
a3−a2=−12−(−12)
=0
a4−a3=−12−(−12)
=0
This shows that the difference is same, so the given series is in A.P. with common difference 0. The next three terms are,
a5=−12+(0)
=−12
a6=−12+(0)
=−12
a7=−12+(0)
=−12
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