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Question

Check the correctness of the equation FC=mv2r, where the terms have their.

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Solution

Dimensional formula of force =m×a

mxa=mxvt

L.H.S=F=M1L1T2(1)

R.H.S=mv2r
=M1(L1T1)2L

=M1L2T2L

=M1L1T2(2)

By equation 1 and 2
L.H.S=R.H.S
Since the dimensions of F and
mV2r are equal... so equation is dimensionally correct


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