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Question

Check the correctness of the relation Snth=u+a2(2n1), where u is initial velocity, a is acceleration and Snthis the distance travelled by the body in nth second.

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Solution

snth=μ+a2(2n1)

The real formula is ;

μ(1)+a2(1) (2n - 1 )

where 1 represent 1 sec as times

LHS = [ L ]

[ L ] = μ(1)=[LT1][T]

= [ L ]

aa(1)[2n1] = LT2 [ T ] [ T ]

= L

[ L ] = [ L ] + [ L ]

hence the formula is correct

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