Question

Check the divisibility conditions of $3,4$ for the following numbers

$\left(i\right)63712$

$\left(ii\right)2314$

$\left(iii\right)78962$

$\left(iv\right)10038$

$\left(v\right)20701$

Answer 1

A natural number is divisible by $3$ if and only if, the sum of the digits is divisible by $3$

A natural number is divisible by $4$ if and only if, the number formed by the last two digits is divisible by $4$ or last two digits in the given number are zeros

Numbers	Divisibility by $3$	Divisibility by $4$
$\left(i\right)63712$	$6+3+7+1+2=19$ is not divisible by $3$.Hence $63712$ is not divisible by $3$	The last two digit is $12$ is divisible by $4$ since $4\times 3=12$.Hence $63712$ is divisible by $4$
$\left(ii\right)2314$	$2+3+1+4=10$ is not divisible by $3$.Hence $2314$ is not divisible by $3$	The last two digit is $14$ is not divisible by $4$ .Hence $23142$ is not divisible by $4$
$\left(iii\right)78962$	$7+8+9+6+2=32$ is not divisible by $3$.Hence $78962$ is not divisible by $3$	The last two digit is $62$ is not divisible by $4$ .Hence $78962$ is not divisible by $4$
$\left(iv\right)10038$	$1+0+0+3+8=12$ is divisible by $3$.Hence $10038$ is divisible by $3$	The last two digit is $38$ is not divisible by $4$ .Hence $10038$ is not divisible by $4$
$\left(v\right)20701$	$2+0+7+0+1=10$ is not divisible by $3$.Hence $20701$ is divisible by $3$			The last two digit is $01$ is not divisible by $4$ .Hence $20701$ is not divisible by $4$