Question

Check the divisibility of $96128$ by $3,4,8$ and $9$.

Answer 1

Divisibility rule of $3$- A number is divisible by $3$ if the sum of its digits is divisible by$3$.

$96128$ is not divisible by $3$ as the sum of its digits $9+6+1+2+8=26$ which is not divisible by$3$.

Divisibility rule of $4$- A number is divisible by $4$ if the number formed by its last two digits i.e. tens and ones is divisible by$4$.

$96128$ is divisible by $4$ as a number formed by the last two digits, i.e., $28$ is divisible by$4$.

Divisibility rule of $8$- A number is divisible by $8$ if the number formed by the last three digits, i,e., hundreds, tens, and ones is divisible by$8$.

$96128$ is divisible by $8$ as $128$ is divisible by$8$.

Divisibility rule of $9$- A number is divisible by $9$ it the sum of its digits is divisible by $9$.

$96128$ is not divisible by $9$ as $9+6+1+2+8=26$ which is not divisible by$9$.