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Byju's Answer
Standard VIII
Mathematics
Addition and Subtraction of Algebraic Expression
Check the equ...
Question
Check the equality of the following determinant:
∣
∣ ∣
∣
x
−
2
2
x
−
3
3
x
−
4
x
−
4
2
x
−
9
3
x
−
16
x
−
8
2
x
−
27
3
x
−
64
∣
∣ ∣
∣
=
0
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Solution
∣
∣ ∣
∣
x
−
2
2
x
−
3
3
x
−
4
x
−
4
2
x
−
9
3
x
−
16
x
−
8
2
x
−
27
3
x
−
64
∣
∣ ∣
∣
=
0
∣
∣ ∣
∣
x
2
x
3
x
x
2
x
3
x
x
2
x
3
x
∣
∣ ∣
∣
−
∣
∣ ∣
∣
2
3
4
4
9
16
8
27
64
∣
∣ ∣
∣
=
0
∣
∣ ∣
∣
x
2
x
3
x
x
2
x
3
x
x
2
x
3
x
∣
∣ ∣
∣
−
∣
∣ ∣ ∣
∣
2
3
4
2
2
3
2
4
2
2
3
3
3
4
3
∣
∣ ∣ ∣
∣
=
0
∣
∣ ∣
∣
x
2
x
3
x
x
2
x
3
x
x
2
x
3
x
∣
∣ ∣
∣
−
2
×
3
×
4
∣
∣ ∣ ∣
∣
1
3
4
2
3
4
2
2
3
2
4
2
∣
∣ ∣ ∣
∣
=
0
⇒
24
[
1
(
48
−
36
)
−
1
(
32
−
16
)
+
1
(
18
−
12
)
]
24
[
12
−
16
+
6
]
=
24
[
12
−
10
]
=
48
∣
∣ ∣
∣
x
2
x
3
x
x
2
x
3
x
x
2
x
3
x
∣
∣ ∣
∣
−
48
=
0
x
3
∣
∣ ∣
∣
1
2
3
1
2
3
1
2
3
∣
∣ ∣
∣
−
48
=
0
⇒
x
3
(
0
)
−
48
=
0
Hence it is not true for any values of
x
Suggest Corrections
0
Similar questions
Q.
Solve for
x
:
∣
∣ ∣
∣
x
−
2
2
x
−
3
3
x
−
4
x
−
4
2
x
−
9
3
x
−
16
x
−
8
2
x
−
27
3
x
−
64
∣
∣ ∣
∣
=
0
Q.
If
⎛
⎜
⎝
x
−
2
2
x
−
3
3
x
−
4
x
−
4
2
x
−
9
3
x
−
16
x
−
8
2
x
−
27
3
x
−
64
∣
∣ ∣
∣
=
0
,
then
x
=
.