Check the given value is a solution of the given equation or not.
$3 x^{2} - 2 x - 1 = 0, x = 1$

True

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False

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Solution

The correct option is A True
Given : $3 x^{2} - 2 x - 1 = 0$

$\Rightarrow$ $3 x^{2} - 3 x + x - 1 = 0$
$\Rightarrow$ $3 x (x - 1) + 1 (x - 1) = 0$
$\Rightarrow$ $(x - 1) (3 x + 1) = 0$
$\Rightarrow$ $x - 1 = 0$ and $3 x + 1 = 0$
$\Rightarrow$ $x = 1$ and $= - \frac{1}{3}$

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Similar questions

Q. Check whether the given equation is a quadratic equation or not.

3 x^{2} - 4 x + 2 = 2 x^{2} - 2 x + 4

In each of the following, determine whether the given values are solutions (roots) of the equation or not :
(i) $3 x^{2} - 2 x - 1$ = 0; x = 1
(ii) $x^{2} + 6 x + 5$ = 0; x = – 1, x = – 5
(iii) $x^{2} + x - 4 = 0$ ; x = – 2

Check whether given equation is a quadratic equation or not : $\frac{x + 5}{1} = \frac{2 x + 10}{x - 6}$

Q. Question 2(d)
Check whether the value given in the brackets is a solution to the given equation or not:
4p-3=13(p=1)

Q. Check whether given equation is quadratic or not

x^{2} - 2 x - \sqrt{x} - 5 = 0

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Check the given value is a solution of the given equation or not.3x2−2x−1=0,x=1

The correct option is A TrueGiven : 3x2−2x−1=0⇒ 3x2−3x+x−1=0⇒ 3x(x−1)+1(x−1)=0⇒ (x−1)(3x+1)=0⇒ x−1=0 and 3x+1=0⇒ x=1 and =−13

Check the given value is a solution of the given equation or not.
$3 x^{2} - 2 x - 1 = 0, x = 1$

The correct option is A True
Given : $3 x^{2} - 2 x - 1 = 0$

$\Rightarrow$ $3 x^{2} - 3 x + x - 1 = 0$
$\Rightarrow$ $3 x (x - 1) + 1 (x - 1) = 0$
$\Rightarrow$ $(x - 1) (3 x + 1) = 0$
$\Rightarrow$ $x - 1 = 0$ and $3 x + 1 = 0$
$\Rightarrow$ $x = 1$ and $= - \frac{1}{3}$