Check whether 102 n -1-1 is divisible by-A- 11B- 2C- 5D- 4

The correct option is A 11Here, 10^2n +1 1 can be written as nbsp; 999 .... 999 (2n + 1 times). The digits in all places are 9. Hence, it is divisible by 3 a ...

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Byju's Answer

Standard VIII

Mathematics

Divisibility Test of 11

Check whether...

Question

Check whether $10^{2 n + 1} - 1$ is divisible by:

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Solution

The correct option is A 11
Here,
$10^{2 n + 1} - 1$ can be written as
999 .... 999 (2n + 1 times). The digits in all places are 9. Hence, it is divisible by 3 and 9. Their sum of digits in odd places and sum digits even places are same. Their difference is 0. Hence, it is divisible by 11.

Suggest Corrections

Check whether 102n+1−1 is divisible by:

The correct option is A 11Here, 102n+1−1 can be written as 999 .... 999 (2n + 1 times). The digits in all places are 9. Hence, it is divisible by 3 and 9. Their sum of digits in odd places and sum digits even places are same. Their difference is 0. Hence, it is divisible by 11.

Check whether $10^{2 n + 1} - 1$ is divisible by:

The correct option is A 11
Here,
$10^{2 n + 1} - 1$ can be written as
999 .... 999 (2n + 1 times). The digits in all places are 9. Hence, it is divisible by 3 and 9. Their sum of digits in odd places and sum digits even places are same. Their difference is 0. Hence, it is divisible by 11.