Check whether ā105 is a term of the A.P. 12,10,8,6 .........
A
−105 is not a term of this A.P.
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B
105 is a term of this A.P.
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C
−105 is an integer
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D
105 is not an integer
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Solution
The correct option is A−105 is not a term of this A.P. Given series is 12,10,8,6,....
Thus a=12,d=−2,an=−105 Let −105 be the nth term of this A.P. Since, an=a+(n−1)d ⇒105=12+(n−1)(−2) ⇒−105−12=−2n+2 ⇒−117−2=−2n ⇒n=−119−2 Clearly, n is an integer after solving this. Therefore, −105 is not a term of this A.P.