check whether 12n cannot end with the digit 0 or 5 for any natural number n
Here, Number=12n where n stand for any natural number .
Now 12n= (22 x3)n
Now , For 12n to end with 0, it should have 2 as well as 5 in its Prime factors to end with 0, Also to end with 5 , it requires at least a single multiple of 5 in its Prime Factors, So 12n cannot end with the digit 0 or 5.