Check whether $3$ is zero of polynomial $2 x^{3} - x^{2} - 13 x - 6$ .

True

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False

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Solution

The correct option is A True
Substitute $x = 3$ in $p (x) = 2 x^{3} - x^{2} - 13 x - 6$
If $p (3) = 0$ then 3 is zero of the polynomial $p (x)$

$\Rightarrow 2 x^{3} - x^{2} - 13 x - 6$
$\Rightarrow 2 \times (3^{3}) - (3^{2}) - 13 \times 3 - 6$
$\Rightarrow 54 - 9 - 39 - 6$
$\Rightarrow 0$

Hence, $3$ is zero of this polynomial

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Similar questions

α, β

γ

2 x^{3} + x^{2} - 13 x + 6

α β γ =

If α, β, γ are the zeros of the polynomial 2x³ + x² - 13x + 6, then the value of αβγ is

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x^{2} - 9

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p (x) = x^{2} + 7 x + 10

p (x) = 2 x^{3} + 9 x^{2} + 13 x + 6, S (x) = 2 x^{2} + 5 x + 3

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