here a=4 common difference=7-4=3 nth term of an AP is given by a+(n-1)d Let 307 be the nth term then 307=4+(n-1)3 307-4=(n-1)3 303=(n-1)3 303/3=n-1 101=n-1 therefore n=102
therefore 307 is the 102th term of the given AP
NOTE:If you get n as a fraction then the number will not be in AP