Question

Question 5
Check whether $6^n$ can end with the digit 0 for any natural number n.

Answer 1

If any number ends with a digit 0, it should be divisible by 10.
In other words, it will also be divisible by 2 and 5 as 10 = 2 $\times$ 5
Prime factorisation of $6^n=(2\times 3{)}^n$
It can be observed that 5 is not in the prime factorization of $6^n$.
Hence, for any value of n, $6^n$ will not be divisible by 5.
Therefore, $6^n$ cannot end with the digit 0 for any natural number n.