Question

Check whether $6^n$ can end with the digit 0 or any $n\in N$

Answer 1

$6^n=(2.3{)}^n=2^n{.3}^n$

$\Rightarrow 6^n$ contains $2^n$ digit dose not contain

any multiple of 5 $\therefore$ it is not desert

by 10 and have can not and with 0 $\forall nEN$