A three-digit number ABC is divisibile by 7 when
(2A + 3B + C) is divisible by 7.
[1 mark]
Here, in the number 952, A = 9, B = 5 and C = 2.
[0.5 mark]
Now, (2A + 3B + C)
= 2(9) + 3(5) + 2
= 18 + 15 + 2
= 35 [1 mark]
Since, 35 is divisible by 7,
Hence, 952 is divisible by 7.
[0.5 mark]