Question

Check whether $\frac{\cos {30}^o+\sin {60}^o}{1+\cos {60}^o+\sin {30}^o}=\frac{\sqrt{3}}{4}$ is true/false ?

• A. True
• B. False

Answer 1

The correct option is B False

As we know that $\cos {30}^{\circ }=\frac{\sqrt{3}}{2},\sin {60}^{\circ }=\frac{\sqrt{3}}{2},\sin {30}^{\circ }=\cos {60}^{\circ }=\frac{1}{2}$

$\frac{\cos {30}^{\circ }+\sin {60}^{\circ }}{1+\cos {60}^{\circ }+\sin {30}^{\circ }}=\frac{\frac{\sqrt{3}}{2}+\frac{\sqrt{3}}{2}}{1+\frac{1}{2}+\frac{1}{2}}=\frac{\sqrt{3}}{2}$

So the given relation is $\text{False}$