Check whether given equation is a quadratic equation or not : $\frac{x + 5}{1} = \frac{2 x + 10}{x - 6}$

True

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False

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Solution

The correct option is A
True

$\frac{x + 5}{1} = \frac{2 x + 10}{x - 6}$

$(x + 5) (x - 6) = (2 x + 10)$

$x^{2} - x - 30 = 2 x + 10$

$\Rightarrow$ $x^{2} - 3 x - 40 = 0$ is in the form of $a x^{2} + b x + c$

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