Question

Check whether $(x+\frac{3}{4}x)(x-8)+10=0$ is a quadratic equations

Answer 1

Given that: $(x+\frac{3}{4}x)(x-8)+10=0$
By simplifying we get:
$x^2-8x+\frac{3}{4}{x}^2-\frac{24}{4}x+10=0$
$4x^2-32x+3x^2-24x+40=0$
$7x^2-56x+40=0$. It is of the form $a{x}^2+bx+c=0$
$\therefore$ It is a quadratic equation.