Check whether the following are quadratic equations: (x−2)(x+1)=(x−1)(x+3)
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Solution
(x−2)(x+1)=(x−1)(x+3)⇒x2−x−2=x2+2x−3⇒3x−1=0
It is not of the form ax2+bx+c=0 as a = 0 in this case.
Hence, the given equation is not a quadratic equation.