2x+y=6
4x-2 y=4
\begin{tabular}{|l|l|l|l|}
\hline\( x \) & 0 & 1 & 2 \\
\hline\( y \) & 6 & 4 & 2 \\
\hline
\end{tabular}
\begin{tabular}{|l|l|l|l|}
\hline\( x \) & 0 & 1 & 2 \\
\hline\( y \) & \( -2 \) & 0 & 2 \\
\hline
\end{tabular}
Here, a1=2,b2=1,c1=6
a1=4,b2=−2,c1=4
∴a1a2=24=12,b1 b2=−12,c1c2=64=32
a1a2≠b1 b2≠c1c2
∴ two lines are consistent