Question

Check whether the following form an AP$\sqrt{3},\sqrt{12},\sqrt{27},\sqrt{48}$ , ...

• A. True
• B. False

Answer 1

The correct option is A True

We can write the given series as
$\sqrt{3},2\sqrt{3},3\sqrt{3},4\sqrt{3}$
Compare the given series with $a_1,a_2,a_3......$
we get
$a_2-a_1=2\sqrt{3}-\sqrt{3}=\sqrt{3}$
$a_3-a_2=3\sqrt{3}-2\sqrt{3}=\sqrt{3}$
and so on.
Since common difference is same and equal to $\sqrt{3}$, therefore given series is AP.