Check whether the following is a quadratic equation or not (2x-1)(x-3)=(X+5)(x-1)

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Solution

(v)(2x−1)(x−3)=(x+5)(x−1)⇒2x2−7x+3=x2+4x−5⇒x2−11x+8=0
It is of the form ax2+bx+c=0
Hence, the given equation is quadratic equation.

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Similar questions

(x - 2) (x + 1) = (x - 1) (x + 3)

(2 x - 1) (x - 3) = (x + 5) (x - 1)

(2 x - 1) (x - 3) = (x + 5) (x - 1)

(2 x - 1) (x - 3) = (x + 5) (x - 1)

(x - 3) (2 x + 1) = x (x + 5)

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