Check whether the following is a quadratic equation : $(x - 2)^{2} + 1 = 2 x - 3$

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Solution

$(x - 2)^{2} + 1 = 2 x - 3$
$x^{2} - 4 x + 5 = 2 x - 3$
$x^{2} - 6 x + 8 = 0$
It is of the form $a x^{2} + b x + c = 0$ .
Therefore, the given equation is a quadratic equation.

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Similar questions

(x - 2) (x + 1) = (x - 1) (x + 3)

(x - 3) (2 x + 1) = x (x + 5)

(2 x - 1) (x - 3) = (x + 5) (x - 1)

(x + 2)^{3} = 2 x (x^{2} - 1)

(x - 3) (2 x + 1) = x (x = 5)

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