Question

Check whether the following is quadratic equation.
$(x+1{)}^2=2(x-3)$

Answer 1

$(x+1{)}^2=2(x-3)$

$\Rightarrow$ $x^2+2x+1=2x-6$

$\Rightarrow$ $x^2+2x+1-2x+6=0$

$\Rightarrow$ $x^2+7=0$

$\Rightarrow$ A quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared

$\Rightarrow$ Comparing given equation $x^2+7=0$ with standard form of quadratic equation $a{x}^2+bx+c=0.$

$\Rightarrow$ We get, $a=1,b=0,c=7$

$\therefore$ The given equation is quadratic equation.