For divisible by
7: To check if a number is evenly divisible
by
7 take the last digit of the number, double it and then subtract the
result from the rest of the number. If the resulting number is evenly
divisible by
7, so is the original number.
The Rule is to be applied as follows
(a)
427⇒42−(7×2)=28 which is divisible by
7.
Therefore, number is divisible by
7.
(b)
3514⇒351−(4×2)=343 Now, Further applying the same rule 34−(3×2)=28 which is divisible by 7.
Therefore, number is divisible by 7.
(c) 861⇒86−(1×2)=84 which is divisible by 7.
Therefore, number is divisible by 7.
(d) 4676⇒467−(6×2)=455
Now, Further applying the same rule 45−(5×2)=35 which is divisible by 7.
Therefore, number is divisible by 7.