Question

Check whether the number5832 and 6400 and perfect cube or not.

Answer 1

Dear student
$$\begin{gathered} \sqrt[3]{5832}=\sqrt[3]{2\times 2\times 2\times 3\times 3\times 3\times 3\times 3\times 3}=2\times 3\times 3=18 \\ So,5832iscuberootof18 \\ \sqrt[3]{6400}=\sqrt[3]{2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 5\times 5}=2\times 2\sqrt[3]{4\times 25}=4\sqrt[3]{100} \\ So,6400isnotaperfectcuberoot. \end{gathered}$$
regards