The equation of curve is y=2x2−6x.
Differentiating with respect to x gives slope of the tangent i.e.,
dydx=4x−6
Let, m1 be the slope of tangent at (0,0) and m2 be the slope of tangent at (3,0)
∴m1=4(0)−6=−6 and m2=4(3)−6=6
Clearly, m1m2=−6×6=−36≠−1
∴ The tangents of the given curve at (0,0) and (3,0) are not at right angle.