Chemical formula of blue vitrol and caustic potash are respectively:

C u S O_{4}, N a O H

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C u S O_{4} .5 H_{2} O, K O H

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C u S O_{4} .5 H_{2} O, N a O H

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C o S O_{4} .7 H_{2} O, K O H

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Solution

The correct option is B $C u S O_{4} .5 H_{2} O, K O H$
$Blue vitrol : C u S O_{4} .5 H_{2} O Caustic potass : K O H$

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