Chetan deposited Rs. $1200$ per month in a recurring deposit account for one year at $6$ % p.a. Find the interest received by him.

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Solution

Time period $= 1$ year $= 12$ months

Interest received by him
$= P \frac{n (n + 1)}{2} \frac{1}{12} \frac{R}{100}$

$= 1200 \frac{(12) (13)}{2} \frac{1}{12} \frac{6}{100}$

$= 12 \frac{13}{2} \times 6 = 156 \times 3 = 468$ .

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Chetan deposited Rs. 1200 per month in a recurring deposit account for one year at 6% p.a. Find the interest received by him.

Time period =1 year =12 monthsInterest received by him=Pn(n+1)2112R100=1200(12)(13)21126100=12132×6=156×3=468.

Chetan deposited Rs. $1200$ per month in a recurring deposit account for one year at $6$ % p.a. Find the interest received by him.

Time period $= 1$ year $= 12$ months

Interest received by him
$= P \frac{n (n + 1)}{2} \frac{1}{12} \frac{R}{100}$

$= 1200 \frac{(12) (13)}{2} \frac{1}{12} \frac{6}{100}$

$= 12 \frac{13}{2} \times 6 = 156 \times 3 = 468$ .