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Mole Concept

Chile salt pe...

Question

Chile salt petre is a natural source of $N a N O_{3}$ which also contains $N a I O_{3}$ . The $N a I O_{3}$ can be used as a source of iodine produced in the following reactions:

$I O_{3}^{-} + 3 H S O_{3}^{-} ⟶ I^{-} + 3 H^{+} 3 S O_{4}^{2 -}$ ... (i)
$5 I^{-} + I O_{3}^{-} + 6 H^{+} ⟶ 3 I_{2} (s) + 3 H_{2} O$ ... (ii)

$1.00$ L of the starting solution which contains $5.80$ g $N a I O_{3}$ per litre is treated with stoichiometric quantity of $N a H S O_{3}$ . Further, a quantity of the starting solution is added to the reaction mixture to bring about the second reaction. $[I = 127, N a = 23, S = 32]$
How many equivalents of $I O_{3}^{-}$ are present in one mole of $N a I O_{3}$ in step (i)?

A

2

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B

4

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C

6

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D

8

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Solution

The correct option is D $6$
$I^{-}$ formed in step $I = \frac{5.8}{198}$ mol

$I O_{3}^{-}$ required in step $I I = \frac{5.9}{198 \times 5}$ mol $= \frac{5.8 \times 198}{198 \times 5}$ g $N a I O_{3}$ $= 1.16$ g $N a I O_{3}$
$∴$ Volume $= \frac{1.16}{5.8} = 0.2 L$
$I O_{3}^{-} + 5 ⟶ I^{-} - 1$
Change in oxidation number $= 6$ units
Thus, one mole $N a I O_{3}$ is $6$ equivalents.

Hence, the correct option is $(C)$ .

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Similar questions

Chile salt petre is a natural source of

N a N O_{3}

which also contains

N a I O_{3}

N a I O_{3}

can be used as a source of iodine produced in the following reactions:

I O_{3}^{-} + 3 H S O_{3}^{-} ⟶ I^{-} + 3 H^{+} 3 S O_{4}^{2 -}

5 I^{-} + I O_{3}^{-} + 6 H^{+} ⟶ 3 I_{2} (s) + 3 H_{2} O

1.00

L of the starting solution which contains

5.80

N a I O_{3}

per litre is treated with stoichiometric quantity of

N a H S O_{3}

. Further, a quantity of the starting solution is added to the reaction mixture to bring about the second reaction.

[I = 127, N a = 23, S = 32]

How many equivalents of

I O_{3}^{-}

are used in step (ii)?

Chile salt petre is a natural source of

N a N O_{3}

which also contains

N a I O_{3}

N a I O_{3}

can be used as a source of iodine produced in the following reactions:

I O_{3}^{-} + 3 H S O_{3}^{-} ⟶ I^{-} + 3 H^{+} 3 S O_{4}^{2 -}

5 I^{-} + I O_{3}^{-} + 6 H^{+} ⟶ 3 I_{2} (s) + 3 H_{2} O

1.00

L of the starting solution which contains

5.80

N a I O_{3}

per litre is treated with stoichiometric quantity of

N a H S O_{3}

. Further, a quantity of the starting solution is added to the reaction mixture to bring about the second reaction.

[I = 127, N a = 23, S = 32]

How many grams of

N a H S O_{3}

are required in step (i)?

Chile salt petre is a natural source of

N a N O_{3}

which also contains

N a I O_{3}

N a I O_{3}

can be used as a source of iodine which produced in the following reactions:

I O_{3}^{-} + 3 H S O_{3}^{-} ⟶ I^{-} + 3 H^{+} 3 S O_{4}^{2 -}

5 I^{-} + I O_{3}^{-} + 6 H^{+} ⟶ 3 I_{2} (s) + 3 H_{2} O

1.0

L of the starting solution which contains

5.80

N a I O_{3}

per litre is treated with stoichiometric quantity of

N a H S O_{3}

. A further quantity of the starting solution is added to the reaction mixture to bring about the second reaction.

(Atomic mass of

I = 127, N a = 23, S = 32

___________ equivalents of

I O_{3}^{-}

are present in one mole of

N a I O_{3}

Chile saltpetre is a natural source of

N a N O_{3}

which also contains

N a I O_{3}

N a I O_{3}

can be used as a source of iodine produced in the following reactions:

{I O_{3}}^{-} + 3 {H S O_{3}}^{-} \to I^{-} + 3 H^{+} + 3 {S O_{4}}^{2 -}

5 I^{-} + {I O_{3}}^{-} + 6 H^{+} \to 3 I_{2} (s) + 3 H_{2} O

1.0

L of the starting solution which contains

5.80

N a I O_{3}

is treated with stoichiometric quantity of

N a H S O_{3}

. Further, a quantity of the starting solution is added to the reaction mixture to bring about the second reaction

[I = 127, N a = 23, S = 32]

How many equivalents of

{I O_{3}}^{-}

are used in the above reaction in step (ii)?

Chile salt petre is a natural source of

N a N O_{3}

which also contains

N a I O_{3}

N a I O_{3}

can be used as a source of iodine which produced in the following reactions:

I O_{3}^{-} + 3 H S O_{3}^{-} ⟶ I^{-} + 3 H^{+} 3 S O_{4}^{2 -}

5 I^{-} + I O_{3}^{-} + 6 H^{+} ⟶ 3 I_{2} (s) + 3 H_{2} O

1.0

L of the starting solution which contains

5.80

N a I O_{3}

per litre is treated with stoichiometric quantity of

N a H S O_{3}

. A further quantity of the starting solution is added to the reaction mixture to bring about the second reaction.

(Atomic mass of

I = 127, N a = 23, S = 32

What additional volume (in L) of the starting solution must be added in step (ii)?

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