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Question

Chile salt petre is a natural source of NaNO3 which also contains NaIO3. The NaIO3 can be used as a source of iodine produced in the following reactions:

IO3+3HSO3I+3H+3SO24 ... (i)
5I+IO3+6H+3I2(s)+3H2O ... (ii)

1.00 L of the starting solution which contains 5.80 g NaIO3 per litre is treated with stoichiometric quantity of NaHSO3. Further, a quantity of the starting solution is added to the reaction mixture to bring about the second reaction. [I=127,Na=23,S=32]
How many equivalents of IO3 are present in one mole of NaIO3 in step (i)?

A
2
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B
4
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C
6
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D
8
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Solution

The correct option is D 6
I formed in step I=5.8198 mol

IO3 required in step II=5.9198×5 mol =5.8×198198×5 g NaIO3 =1.16 g NaIO3
Volume =1.165.8=0.2L
IO3+5I1
Change in oxidation number =6 units
Thus, one mole NaIO3 is 6 equivalents.

Hence, the correct option is (C).

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