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Question

Chile salt petre is a natural source of NaNO3 which also contains NaIO3. The NaIO3 can be used as a source of iodine which produced in the following reactions:
IO3+3HSO3I+3H+3SO24 ... (i)
5I+IO3+6H+3I2(s)+3H2O ... (ii)
1.0 L of the starting solution which contains 5.80 g NaIO3 per litre is treated with stoichiometric quantity of NaHSO3. A further quantity of the starting solution is added to the reaction mixture to bring about the second reaction.
(Atomic mass of I=127, Na=23, S=32)
How many equivalents of IO3 are used in step (ii)?

A
6
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B
5
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C
0.06
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D
0.035
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Solution

The correct option is D 0.035
IO3+5I1

Change in oxidation number =6 units

Thus, one mole NaIO3=6 equivalents

1.16 g NaIO3=1.16198 mol =6.96198 equivalents (since IO3=6I)

=0.035 equivalents

Hence, the correct option is (D).

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