Question

Chloride of an element is given by the formula $MC{I}_x$ and it is $100$% ionised in $0.01$ M aqueous solution. Then :

• A. If $\left[C{I}^{-}\right]$ = $0.03$ M then, the value of $x$ is $3$.
• B. If $\left[C{I}^{-}\right]$ =$0.05$ M then, the value of x is $5$
• C. $\left[M^{x+}\right]$ = $0.01$ M. irrespective of $\left[C{I}^{-}\right]$
• D. $\left[M^{x+}\right]$ depends on $\left[C{I}^{-}\right]$

Answer 1

Answer: (A), (B), (C)

The correct options are
A If $\left[C{I}^{-}\right]$ = $0.03$ M then, the value of $x$ is $3$.
B $\left[M^{x+}\right]$ = $0.01$ M. irrespective of $\left[C{I}^{-}\right]$
C If $\left[C{I}^{-}\right]$ =$0.05$ M then, the value of x is $5$

One mole of $MC{I}_x$ contains $x$ moles of $C{l}^{-}$ ions.
Hence, $\left[C{I}^{-}\right]=x\times 0.01$
For option A, $\left[C{I}^{-}\right]=0.03$ or $0.03=x\times 0.01$. Hence, $x=3$.
For option B, $\left[C{I}^{-}\right]=0.05$ or $0.05=x\times 0.01$. Hence, $x=5$.
For option A, $\left[C{I}^{-}\right]=0.01$ or $0.01=x\times 0.01$. Hence, $x=1$.
In all cases, $\left[M^{x+}\right]=0.01M$.