Chlorine atom in its third excited state with fluorine to form a compound $X$ . The formula and shape of $X$ are:

C l F_{5}

, pentagonal

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C l F_{4}

, tetrahedral

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C l F_{4}

, pentagonal bipyramidal

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C l F_{7}

, pentagonal bipyramidal

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Solution

The correct option is D $C l F_{7}$ , pentagonal bipyramidal
From the diagram, it is clear that chlorine has $7$ unpaired orbitals each of which can form a bond with fluorine. Hence, hybridization is $s p^{3} d^{3}$ and shape is pentagonal bipyramidal.

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