wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

Chlorine can be prepared by reacting MCI with MnO2. The reaction is represented by the equation,
MnO2(s)+4HCI(aq.)Cl2(g)+MnCl2(aq.)+2H2O(l)
Assuming that the reaction goes to completion, what mass of cone. HCI solution (36% HCI by mass) is needed to produce 2.5 g Cl2 ?

A
5.15 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
14.3 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
19.4 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
26.4 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 14.3 g
4 moles of HCl give 1 mole of Cl2
or 4 x 36.5g HCl give 1x 71g of Cl2
Therefore, weight of HCl required to give 2.5 g Cl2
=4×36.51×71×2.5= 5.14 g
But it is 36% pure
Therefore mass of HCl solution required =100×5.1436 =14.3g


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Bleaching Powder
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon