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Standard IX

Chemistry

Atomic Mass and Atomic Mass Unit

Question 13 C...

Question

Question 13

Chlorine exists in two isotopic forms. Cl - 37 and Cl - 35 but its atomic mass is 35.5. This indicates the ratio of Cl - 37 and Cl - 35 is approximately

(a) 1 : 2 (b) 1 : 1 (c) 1 : 3 (d) 3 : 1

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Solution

Option c is the correct answer.

The fractional atomic mass (35.5) of chlorine is due to the fact that in ordinary chlorine atom, Cl - 37 and Cl - 35 is approximately

$∴$ Average atomic mass of $C l = \frac{3 \times 35 + 1 \times 37}{4} = 35.5 a m u$

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Similar questions

Q. Chlorine exists in two isotopic forms,

C l - 37

and

C l - 35

but its atomic mass is

35.5

. This indicates the ratio of

C l - 37

and

C l - 35

is approximately:

Q. Chlorine has two naturally occurring isotopes,

^{35} C l

and

^{37} C l

. If the atomic mass of

C l

is 35.45, the ratio of natural abundance of

^{35} C l a n d^{37} C l

is closest to

Naturally occurring chlorine consists of two isotopes whose atomic weights are 35 and 37. The atomic weight of natural chlorine is 35.5, then what is the ratio of $C l^{35} t o C l^{37}$ ?

The two isotopes of chlorine are ³⁵₁₇Cl and ³⁷₁₇Cl in the ratio of 3:1. What is the average atomic mass of the chlorine atom?

Q. Chlorine has two naturally occuring isotopes

_{17}^{37} C l

and

_{17}^{35} C l

and average atomic mass of chlorine is

35.5

. The percentage of

_{17}^{37} C l

is:

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Question 13 Chlorine exists in two isotopic forms. Cl - 37 and Cl - 35 but its atomic mass is 35.5. This indicates the ratio of Cl - 37 and Cl - 35 is approximately (a) 1 : 2 (b) 1 : 1 (c) 1 : 3 (d) 3 : 1

Option c is the correct answer. The fractional atomic mass (35.5) of chlorine is due to the fact that in ordinary chlorine atom, Cl - 37 and Cl - 35 is approximately ∴ Average atomic mass of Cl=3×35+1×374=35.5 amu

Question 13

Chlorine exists in two isotopic forms. Cl - 37 and Cl - 35 but its atomic mass is 35.5. This indicates the ratio of Cl - 37 and Cl - 35 is approximately

(a) 1 : 2 (b) 1 : 1 (c) 1 : 3 (d) 3 : 1

Option c is the correct answer.

The fractional atomic mass (35.5) of chlorine is due to the fact that in ordinary chlorine atom, Cl - 37 and Cl - 35 is approximately

$∴$ Average atomic mass of $C l = \frac{3 \times 35 + 1 \times 37}{4} = 35.5 a m u$